Problem 26
ABC is an isosceles right triangle, where C = 90°. Points D and E are chosen on AC and BC such that CD = CE. Perpendiculars from C and D to AE meet the hypotenuse AB at F and G. Prove that:
BF = GF
Here’s a simulation that illustrates the problem.
Try dragging the A, C, and D. Are BF and GF always equal? How can we prove the same?
Solution
[coming soon]
Problem Source: CutTheKnot
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